he unknown solution is prepared by mixing CaCO3(s) and HCl(aq). The H2CO3 produced in this reaction decomposes to CO2 (g) and H2O. Write the complete chemical equation for this reaction, indicating the state of each species. If ionic compounds dissociate, separate the ions in the equation.

CaCO₃(s) + 2 H⁺(aq) + 2 Cl⁻(aq) ⇒ Ca²⁺(aq) + 2 Cl⁻(aq) + H₂O(l) + CO₂(g)

Explanation:

Let's consider the molecular equation that occurs when CaCO₃(s) reacts with HCl(aq).

CaCO₃(s) + 2 HCl(aq) ⇒ CaCl₂(aq) + H₂O(l) + CO₂(g)

The complete ionic equation includes all the ions and the compounds that do not dissociate in water.

CaCO₃(s) + 2 H⁺(aq) + 2 Cl⁻(aq) ⇒ Ca²⁺(aq) + 2 Cl⁻(aq) + H₂O(l) + CO₂(g)

the answer for sodium is 0.186

the answer for rubidium is 0.251

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

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