Cho m gam FeO tác dụng hết với dung dịch H2SO4, thu được 200 ml dung dịch FeSO4 1M. Giá trị của m là

The mass of required is 14.37 g

Explanation:

Molarity is calculated by using the equation:

......(1)

We are given:  

Molarity of iron (II) sulfate = 1 M

Volume of solution = 200 mL = 0.200 L (Conversion factor: 1 L = 1000 mL)

Putting values in equation 1, we get:

The chemical equation for the reaction of FeO with sulfuric acid follows:

By stoichiometry of the reaction:

If 1 mole of iron (II) sulfate is produced by 1 mole of FeO

So, 0.200 moles of iron (II) sulfate will produce = of FeO

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

We know, molar mass of = 71.84 g/mol

Putting values in above equation, we get:

Hence, the mass of required is 14.37 g

first one is the correct answer

- lead + phosphoric acid = hydrogen + lead(ii) phosphate