Os produtos da combustão do H₂S e SO₂ gasoso são mostrados em reações abaixo. H₂(g) + S(s) → H₂S(g) Δ H = -21 KJ S(s) + O₂(g) → SO₂ (g) Δ H = -297 K H₂(g) + 1/2O₂(g) → H₂O(g) Δ H = -242 KJ conclui-se que a energia desprendida na combustão de 1 mol de H₂S(g) segunda a equação é: H₂(g) + 1/2O₂(g) → SO₂ (g) + H₂O(g) Δ H = ? * 1 ponto
a) - 67 Kj
b) + 34 Kj
c) - 560 Kj
d) -34 Kj
e) - 518 Kj

answer: option (b) is the correct answer.

explanation:

a covalent bond is formed by sharing of electrons. whereas polarity arises due to difference in electronegativity of two atoms.

therefore, more is the electronegativity of an atom which combines with the titanium, more readily it will induce a partial positive and negative charge.

thus, out of the given options fluorine is most electronegative and has an incomplete octet. therefore, it will readily combine with titanium to share the electrons and complete its octet.