Consider the dehydration of 2-propanol in sulfuric acid: There is a scheme of a reaction where CH3 CH CH3 with an OH group attached to the second carbon atom dehydrated in the presence of H2SO4. Draw the structure for the product of the dehydration of 2-propanol.

CH2=CH-CH3

Explanation:

One of the ways of preparing alkenes is by dehydration of alcohols using sulphuric acid. The sulphuric acid merely acts as a catalyst in the process.

It begins with the protonation of the -OH group. This is followed by loss of water molecule since water is a good leaving group.

Loss of a proton now completes the mechanism and regenerates the acid catalyst.

The mechanism of dehydration of 2-propanol as well as the product formed in the process is shown in the image attached to this answer.

explanation:

metals have excess of electrons whereas non-metals have deficiency of electrons. thus, in order to gain stability metals easily donate their electrons to the non-metals.

for example, electronic configuration of sodium is and electronic configuration of phosphorous is .

when a phosphorous atom and sodium atom combine together then sodium will donate is extra one electron to the phosphorous atom. as a result there will be formation of ionic bond between sodium and phosphorous.

the reaction will be as follows.

there, are three sodium sodium atoms and each of them will donate its one extra electron to phosphorous atom. thus, the sub-shell of phosphorous gets completely filled.  

thus, we can conclude that electrons are transferred from atoms of sodium to atoms of phosphorous. this transfer makes the sodium atoms donate one electron and the phosphorous atoms to gain one electron. as a result, the sodium and phosphorus atoms strongly attract each other.

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