PLEASE HELP The average number of drops of NaHCO3 in the titration lab was 142. Calculate the number of moles of NaCHO3 that were required to neutralize the CH3COOH in the vinegar.
- 1 mole of acetic acid was required for 2 moles of sodium bicarbonate
- 1 mole of acetic acid was required for 1 mole of sodium bicarbonate
- 2 mole of acetic acid was required for 1 mole of sodium bicarbonate
- 1 mole of acetic acid was required for 3 mole of sodium bicarbonate

The correct option is 1 mole of acetic acid was required for 2 moles of sodium bicarbonate

Explanation:

We are given:

Average number of drops of sodium bicarbonate = 142

The chemical equation for the reaction of sodium bicarbonate and acetic acid in vinegar follows:

From the stoichiometry of the reaction:

1 mole of sodium carbonate reacts with 1 mole of acetic acid in vinegar.

Hence, the correct option is 1 mole of acetic acid was required for 2 moles of sodium bicarbonate

in chemistry, adhesion and cohesion are attractive forces that exist between molecules. they hold the molecules together from each other. they are different in that adhesive force exists between molecules of different substance while cohesive force happens between molecules of same substance.

adhesion between water and glass causes water molecules at the edge of water and glass interface to climb up the wall in a narrow glass tube. this is called capillary action. cohesion is what gives glass its shape and causes water to form a droplet.

the dissociation of nickel hydroxide is follows:

the concentration of hydroxide ion is

the equilibrium constant value of nickel hydroxide is = 6.1 * 10^-^1^6 and thus equilibrium equation can be written as:

thus, concentration of ni is 0.23 * 10^-^4 mol /l