In the chemical reaction between aqueous magnesium chloride and sodium metal, what chemical amount (mol) of magnesium metal can be precipitated (produced) with 12.6 mol of sodium metal?

6.3moles

Explanation:

The balanced equation of the reaction described above between aqueous magnesium chloride and sodium metal is as follows:

MgCl2(aq) + 2Na(s) → 2NaCl(aq) + Mg(s)

From the above equation, 2 moles of sodium metal (Na) produces 1 mole of Magnesium metal (Mg)

Hence, 12.6 mol of Na will produce (12.6/2) mol of Mg.

12.6/2 = 6.3moles of Mg metal.

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nacl or sodium chloride is an ionic compound. this is because an ionic compound pertains to a compound that consists of positively and negatively charged ions. in this case, na (sodium) has a tendency to lose one electron when it reacts with with other atoms, so the resulting sodium ion contains 11 protons and 10 electrons, thus making it positively charged (na+), when chlorine reacts, it usually gains one electron to form an ion called chloride, thus making it negatively charged ( since the ions are oppositely charged, they attract.