Help pls In the following reaction, oxygen is the excess reactant.
SiCl4+O2=SiO2+Cl2
The table shows an experiment record for the above reaction
Trial 1 :starting amount of SiCl4 150g starting amount of O2 200g actual yield of SiO2 49.2g
Trial 2: starting amount of SiCl4 75g Starting amount of O2 50g actual yield of SiO2 25.2
Calculate the percentage yield for SiO2 for trial 1 also determine the leftover reactant for the trial show your work
Based on the percentage yield in trial 2 explain what ratio of reactants is more effective for the given reaction

  the   balanced   equation   for   reaction of   ca metal   with   o2 to   produce   cao   is as below

2 ca+ o2→ 2 cao2

  explanation

the reaction is   balanced     since the   number of atoms   in reactant side is   equal to   number of atoms   in   product side.   for   example   they   are 2   atom of   ca in   reactant   side   and   2   atoms of ca   in   the product side.

  the   process   is a   meet the   requirement   of   redox   reaction because :     calcium   is   oxidized   from   oxidation state 0   to 2+   while   oxygen   is reduced from   oxidation   state   0   to 2-

answer: they produce more slow than unicellular organisms.