I neeed help nowww HELP NOOW What will happen when a piece of magnesium metal is dropped into a beaker
containing a 1 M solution of copper(II) chloride?
Mg2+ + 2e + Mg(s) eº = -2.37 V
Cu2+ + 2e → Cu(s) E° = + 0.34 V

The correct option is B.

Explanation:

The oxidation reaction is defined as the reaction in which a chemical species loses electrons in a chemical reaction.

A reduction reaction is defined as the reaction in which a chemical species gains electrons in a chemical reaction.

The chemical species will undergo a reduction reaction if the value of standard reduction potential is more positive or less negative.

For the given half-reactions:

As the value of standard reduction potential of copper is positive thus, it will undergo a reduction reaction and magnesium will undergo an oxidation reaction.

The half-reaction follows:

Oxidation half-reaction:

Reduction half-reaction:

Overall cell-reaction:

As it can be seen from the reaction that copper is forming as a pure metal in the product thus, it will be deposited and magnesium will be dissolved forming an aqueous solution.

Hence, the correct option is B.

it means there are 3 atoms of oxygen