A spacecraft is traveling at a speed of 2.3 km/sec. It takes 2.5 minutes to pass a small asteroid. how wide is the asteroid (i. e., how far did the spacecraft travel during this time)? Use (distance) = (velocity) x (time)

The spacecraft traveled 345 km during the given time.

Explanation:

To calculate the distance of spacecraft, we use the equation:

We are given:

Velocity = 2.3 km/sec

Time = 2.5 mins = 150 sec             (Conversion factor: 1 min = 60 sec)

Putting values in above equation, we get:

Hence, the spacecraft traveled 345 km during the given time.

confused

confused             hewdejdnjnjsnd

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally