Which statement best rationalizes /\ssys for combustion of methane ch4(g)+2o2(g)→co2(g)+2h2o(g) a. there is a combustion reaction, so /\ssys will be a large negative number.
b. there are no changes os state and no change in nrxn so /\ssys will be small
c. combustion reactions are exothermic, so /\ssys also will be a large negative number
d. this is a combustion reaction so /\ssys will be a large positive number

"among the transition metal elements, manganese and zinc have a slight lowering of electronegativities. the reason behind this is that the nuclear charges of these elements are slightly weaker than the other transition metal elements due to the way their valence electrons are filled up. both manganese and zinc have their valence electrons filled up to the 4th shell with 1 pair of electrons (4s2) completely occupying it. although the electrons in the 3rd shell (3d) are yet to be paired since the outer most shell is filled up, the ability of the nucleus to attract electrons is lessened. hence,   the electronegativity (or the ability to attract electrons) is lessened."

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catya your not at all which answer i've seen you do this on another question!