Find the boiling point of a solution of 2.00 m solution of sodium chloride, NaCl, in water (kb= 0.512°C, bp= 100.0°C)

Boiling point of the given solution is .

Explanation:

Given: Molality = 2.00 m

Now, equation for dissociation of water is as follows.

As it is giving 2 ions upon dissociation. So, the value of i = 2.

Formula used to calculate change in temperature is as follows.

where,

i = Van't Hoff factor

= molal boiling point elevation constant

m = molality

Substitute the values into above formula as follows.

As the boiling point of water is . Hence, the boiling point of solution will be as follows.

Thus, we can conclude that boiling point of the given solution is .

adding or remove a gaseous reactant or product changes the concentrations. if the concentration of reactant or product is increased, the system will shift away from the side in which concentration was increased (i.e. if the concentration of reactants is increased, the system will shift toward the products. if more products are added, the system will shift to form more reactants). conversely, if the concentration of reactant or product is decreased, the system will shift toward the side in which concentration was decreased (i.e. if reactants are removed, the system will shift to form more reactants. if the concentration of products is decreased, the equilibrium will shift toward the products).

explanation:

the answer is d. 74.02