A gas volume of 800.0 litres at _23.00 Celsius and 300.0 torr what would the volume of the gas be at 227.0 Celsius and 600.0 torr of pressure

676 L

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 800 L

Initial temperature (T₁) = 23 °C = 23 + 273 = 296 K

Initial pressure (P₁) = 300 torr

Final temperature (T₂) = 227 °C = 227 + 273 = 500 K

Final pressure (P₂) = 600 torr

Final volume (V₂) =?

The final volume of the gas can be obtained as follow:

P₁V₁/T₁ = P₂V₂/T₂

300 × 800 / 296 = 600 × V₂ / 500

240000 / 296 = 600 × V₂ / 500

Cross multiply

296 × 600 × V₂ = 240000 × 500

177600 × V₂ = 12000000

Divide both side by 177600

V₂ = 12000000 / 177600

V₂ = 675.68 L

V₂ ≈ 676 L

Thus, the final volume of gas is 676 L

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