If a sample of 12.0 grams of fluorine gas at 45.00C has a pressure of 0.544 atm, what is the volume of the container? R = 0.0821 L atm/mol K

15.1 L

4.29 L

30.3 L

2.14 L

Volume of the container is 30.3 L.

Explanation:

Given: Mass = 12 g

Temperature = = (45 + 273) K = 318 K

Pressure = 0.544 atm

R = gas constant = 0.0821 L atm/mol K

Moles is the mass of substance divided by its molar mass.

Hence, moles of fluorine (molar mass = 18.99 g/mol) are as follows.

Formula used to calculate the volume of container is as follows.

PV = nRT

where,

P = pressure

V = volume

n = no. of moles

R = gas constant

T = temperature

Substitute the value into above formula as follows.

Thus, we can conclude that volume of the container is 30.3 L.

the objects have the same charge is correct.

nathan lee