Chemistry, 10.06.2021 14:00, tessadummer0033

What is the Kb of the base PO4^3- given that a 0.48M solution of the base has a pH of 12.70? The equation described by the Kb value is PO4^3-(aq)+H2O(l)⇌HPO4^2-(aq)+OH^−( aq)

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What is the Kb of the base PO4^3- given that a 0.48M solution of the base has a pH of 12.70? The equ...

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