Use the ion-electron method to complete and balance the following skeletal redox equations, occurring in either acidic or basic aqueous solution, as indicated. Identify the oxidation and reduction half reactions in each case. In acidic aqueous solution: Cu+NO3–→Cu2++N2O4
In acidic aqueous solution: XeO3+BrO–3→Xe+BrO–4
In acidic aqueous solution: MnO–4+CH3OH→Mn2++HCO2H
In acidic aqueous solution: Cr2O2–7+I2→Cr3++IO–3
In basic aqueous solution: Pb(OH)2–4+ClO–→PbO2+Cl–
In basic aqueous solution: SO2+MnO–4→SO2–4+MnO2

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole

answer: mole of the gas

answer: mole of the gasexplanation: