Chemistry
Chemistry, 07.06.2021 05:30, 19mcgough

Scientist A produces 83.67 g KMnO4 while Scientist B produces 81.35 g KMnO4. What is the percent yield for Scientist A?

What is the percent yield for Scientist B?

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The equation for the production of potassium permanganate is as follows:

2 MnO2 + 2 KOH + O2 β†’ 2 KMnO4 + H2

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Scientist A produces 83.67 g KMnO4 while Scientist B produces 81.35 g KMnO4. What is the percent yi...

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