How does the ion HCO3- behave as both an acid and a base? A
HCO3- has a hydrogen ion that it can donate as a base. It also has a positive charge that allows it to act as a base and accept a hydrogen ion.

B
HCO3- has a hydrogen ion that it can donate as an acid. It also has a positive charge that allows it to act as a base and accept a hydrogen ion.

C
HCO3- has a hydrogen ion that it can donate as a base. It also has a negative charge that allows it to act as a base and accept a hydrogen ion.

D
HCO3- has a hydrogen ion that it can donate as an acid. It also has a negative charge that allows it to act as a base and accept a hydrogen ion.

if the concentration of products is decreased, the equilibrium will shift toward the products). add an inert gas (one that is not involved in the reaction) to the constant-volume reaction mixture: this will increase the total pressure of the system, but will have no effect on the equilibrium condition.

explanation:

both adhesion and cohesion are attractions.

they are different in that adhesion is the force of attraction between the molecules of two different substances, whereas cohesion is the force of attraction between molecules of the same substance.

possible examples include capillary action, in which the adhesion between water and glass causes the water to rise in a narrow tube against the force of gravity.

because of hydrogen bonding, water is extremely cohesive.

this causes molecules on the surface of water to be drawn inward, which is why drops of water form beads on smooth surfaces.

hope this .

the ideal gas law equation is as follows

pv = nrt

where p - pressure

v - volume

n - number of moles

r - universal gas constant

t - temperature

so if the pressure, volume and temperature are already known

we are left with n and r

since r is the universal gas constant that has a known fixed value then r too is known

so we are left with 'n'

once we know temperature volume and pressure

we can find the number of moles of gas present using the ideal gas law equation

this is not my own answer, this is an answer for the same question by the user blahblahmali. i do not claim ownership of this account.

so what is the problem with your lab report and whats the subject of the lab report? i will you