PLEASE HELP Let’s say a colleague working in the lab needs to create a solution containing 97.9 grams of NaCl. If she has a 3.0 M stock solution of NaCl dissolved in water, how many liters of the stock solution would she need to have 97.9 grams NaCl? Remember the molar mass of NaCl is 58.44 g/mol.

There are 0.558 liters of the stock solution would she need to have 97.9 grams NaCl.

Explanation:

Given: Molarity = 3.0 M

Mass of NaCl = 97.9 g

Molar mass of NaCl = 58.44 g/mol

As number of moles is the mass of substance divided by its molar mass.

So, moles of NaCl are calculated as follows.

Molarity is the number of moles of a substance present in liter of a solution.

Therefore, volume of given solution is calculated as follows.

Thus, we can conclude that there are 0.558 liters of the stock solution would she need to have 97.9 grams NaCl.

c. because step up transformer steps up the input voltage i.e increases the input voltage  

the number of turns are greater on the secondary side of step up transformer  

transformer does not handle dc current