A 9.583 L contains nitrogen gas under a pressure of 4.972 atm at 31.8°C. Calculate the number of moles of nitrogen in the tank.

0.0188

Explanation:

using pv=nRt

where v--volume

p pressure

n number of moles

t temperature in kelvin

R molar gas constant=8.314atmmoldm^-3k^-1

4.972 × 9.583 =n × 8.314 × (31.8 + 273)

note I changed 31.8c to kelvin

making n subject of the formula

n=(4.972 × 9.583)/(8.314 ×(31.8 + 273)

n=(4.972 × 9.583)/(8.314 ×(304.8))

n=0.0188 moles

it is the most commonly accepted one