Given the following set of atoms, write a bond-line formula for a possible constitutional isomer for the compound. Show all formal charges and lone pairs. C atoms H atoms Other3 6 2 Br atoms

Explanation:

Isomers are compounds with the same molecular formula but chemically distinctive structures. Compounds that vary in connectivity, or how the component atoms are related to one another, are known as constitutional isomers. They have distinct functional groups and bonding patterns according to the sequence in which the atoms are linked together.

From the information given:

The compound given is C₃H₆Br₂ and the constitutional isomer of the compound can be seen in the image attached below.

The formal charges are calculated as follows:

Formal charge = valence electron - 1/2(bonding electron) - lone electron

For Br:

Formal charge = 7 - 1/2(2) - 6

Formal charge = 7 - 1 - 6 = 0

For C:

Formal charge = 4 - 1/2(8) - 0

Formal charge = 4 - 4 = 0

For H:

Formal charge = 1 - 1/2(2)

Formal charge = 1 - 1 = 0

c (diamond),

sio2 (quartz)

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