Chemistry, 03.06.2021 21:00, kactus

Write balanced equations and solubility product expressions for the following compounds a. CuBr
b. ZnC2O4
c. Ag2CrO4
d. Hg2Cl2
e. AlCl3
f. Mn3(PO4)3

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answered: idk1561

Explanation:

Solubility product is defined as the product of the concentrations or solubilities of the ions each raised to the power their stoichiometric coefficients present in the solution. It is expressed as $K_{sp}$ .

(a): CuBr

The chemical equation for the dissociation of CuBr into its ions follows:

$CuBr\rightleftharpoons Cu^++Br^-$

The expression of $K_{sp}$ for CuBr follows:

$K_{sp}=[Cu^+][Br^-]$

(b): ZnC_2O_4

The chemical equation for the dissociation of ZnC_2O_4 into its ions follows:

$ZnC_2O_4\rightleftharpoons Zn^{2+}+C_2O_4^{2-}$

The expression of $K_{sp}$ for ZnC_2O_4 follows:

$K_{sp}=[Zn^{2+}][C_2O_4^{2-}]$

(c): Ag_2CrO_4

The chemical equation for the dissociation of Ag_2CrO_4 into its ions follows:

$Ag_2CrO_4\rightleftharpoons 2Ag^{+}+CrO_4^{2-}$

The expression of $K_{sp}$ for Ag_2CrO_4 follows:

$K_{sp}=[Ag^{+}]^2[CrO_4^{2-}]$

(d): ZnC_2O_4

The chemical equation for the dissociation of Hg_2Cl_2 into its ions follows:

$Hg_2Cl_2\rightleftharpoons 2Hg^{+}+2Cl^{-}$

The expression of $K_{sp}$ for Hg_2Cl_2 follows:

$K_{sp}=[Hg^{+}]^2[Cl^{-}]^2$

(e): AlCl_3

The chemical equation for the dissociation of AlCl_3 into its ions follows:

$AlCl_3\rightleftharpoons Al^{3+}+3Cl^{-}$

The expression of $K_{sp}$ for AlCl_3 follows:

$K_{sp}=[Al^{3+}][Cl^{-}]^3$

(f): ZnC_2O_4

The chemical equation for the dissociation of Mn_3(PO_4)_2 into its ions follows:

$Mn_3(PO_4)_2\rightleftharpoons 3Mn^{2+}+2PO_4^{3-}$

The expression of $K_{sp}$ for Mn_3(PO_4)_2 follows:

$K_{sp}=[Mn^{2+}]^3[PO_4^{3-}]^2$

answered: Guest

a solution is always transparent, light passes through with no scattering from solute particles which are molecule in size. the solution is homogeneous and does not settle out. a colloid is intermediate between asolution and a suspension. while asuspension will separate out a colloid will not.

What’s is a suspension, and how is it different from a solution?

answered: Guest

answer : one can design an experiment using a liquid and an additive that can be added to the liquid and observe the chemical changes in the reaction species.

one would need a beaker which is filled with a known amount of the liquid in which thermometer is placed to measure the temperature changes; after addition of the additive to the liquid solution one can note down the temperature change and find whether the reaction is endothermic or exothermic in nature. by subtracting the initial temperature value with the final temperature one can find the temperature changes.

various combinations of liquid and additive can be used. liquid in this case can be a known quantity of water and additives can be epsom salt or without epsom salt the experiment can be conducted to notice the changes. water and ice, hydrogen peroxide and dry yeast, vinegar and baking soda,etc.

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Write balanced equations and solubility product expressions for the following compounds a. CuBr