Solve the given problems showing all work for each. 1. Calculate the molar mass/formula mass of ammonium sulfate -- (NH4)2SO4 , The atomic mass of Nitrogen (N) = 14.0, Sulfur (S) = 32.1, Hydrogen (H) = 1.0, & Oxygen (O) = 16.0 *

The molar mass of ammonium sulfate, (NH₄)₂SO₄ = 132.1 g

Explanation:

The molar mass of a compound is the mass of 1 mole of the given substance.

For a compound the molar mass of the compound is obtained by summing the product of the number of atoms and the atomic masses of the atoms present in the compound.

To calculate the molar mass of ammonium sulfate, (NH₄)₂SO₄:

Atomic masses of the elements are as follows; Nitrogen (N) = 14.0, Sulfur (S) = 32.1, Hydrogen (H) = 1.0, & Oxygen (O) = 16.0

Mass of Nitrogen present = 14.0 × 2 = 28.0 g

Mass of hydrogen present = 1.0 × 4 × 2 = 8.0 g

Mass of sulfur present = 32.1 × 1 = 32.1 g

Mass of oxygen present = 16.0 × 4 = 64.0 g

Molar mass of ammonium sulfate, (NH₄)₂SO₄ = (28.0 + 8.0 + 32.1 + 64.0) g = 132.1 g

Therefore, the molar mass of ammonium sulfate, (NH₄)₂SO₄ = 132.1 g

the correct answer is boyle

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.