g For this titration, you used 10.00 mL of the 250.00 mL vitamin C tablet solution as the analyte. Please enter the volume of titrant added, then calculate the mass of ascorbic acid present in the analyte solution. Then, find this mass as a percentage of the total tablet.

The correct answer should be "electrons orbit the nucleus in circular motions exactly as shown on the classic bohr model."

Answerthis solution will not form a precipitateexplanationsolubility equilbrium:         pbf₂(s)  ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is    (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as    then, we can interpret  q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually  forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product:     since q = 2.7  × 10⁻⁸ < ksp =  4  ×  10⁻⁸, a precipitate will not form.

Answer it is also known as the completion state is untrue of the activation complex;

2licl + 3o2 i yook the test and it was correct.