Someone pls help me How much energy is required to vaporize 112 g of water? ???

6.05 × 10⁴ cal

Explanation:

Step 1: Given and required data

Mass of water (m): 112 g

Enthalpy of vaporization of water (ΔHvap): 540 cal/g

Step 2: Calculate how much energy is required to vaporize 112 g of water

Vaporization is a physical change in which a substance goes from the liquid state to the gaseous state. We can calculate the energy required (Q) using the following expression.

Q = ΔHvap × m

Q = 540 cal/g × 112 g = 6.05 × 10⁴ cal

water at room temperature is flowing through a pipe with pressure taps located 10 ft apart along one section of the pipe, which are connected to a mercury (s=13.6) manometer.

1. a)c-14 has two more protons

2. d)they have different numbers of protons, neutrons, and valence electrons; they are all gases at room temperature.

3. c) iron and nickel.