How many ml of 5.5 mol/L Na (OH) solution is required to make 150 ml 0.01 mol/L Na (OH) solution.

0.27 mL

Explanation:

M1 = 5.5

V1 = ?

M2 = 0.01

V2 = 150

M1V1 = M2V2

(5.5)V1 = (0.01)(150)

V1 = 0.27 mL

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied