Which half-reaction shows conservation of charge? * 5 points A) Cu + e– → Cu+ B) Cu2+ + 2e– → Cu C) Cu+ → Cu + e– D) Cu2+ → Cu + 2e–

B) Cu2+ + 2e– → Cu.

Explanation:

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In this case, in the regard of redox reactions, we must keep in mind that half-reactions show us how the flow of electrons when an element undergoes a change in its oxidation state, say increasing or decreasing. In such a way, if the element is oxidized, increase the oxidation state, we add electrons on the right side and the contrary if the element is reduced, decrease the oxidation state.

In such a way, we can see that the reaction B) Cu2+ + 2e– → Cu, shows how the Cu2+ cations are reduced by adding electrons to produce Cu and thus, conserve the charge.

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