Chemistry, 28.05.2021 01:00, kimlyn58p0wyn0
Fifty grams (50.0) of hot water at a temperature of 65.0°C is mixed with 40.0 grams of cold water. The
final temperature of the mixture is 45.0°C.
a. How much heat energy did the hot water lose?
b. How much heat energy did the cold water gain?
c. What was the initial temperature of the cold water?
Answers: 2
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Will give brainliest it is a lab from k12 here is the linkfor each metal that participated in a chemical change, write the type of metal it is, based on your examination of the periodic table. type your answer here. (score for question 3: of 5 points) were there any metallic compounds that did not react with either the acid or the base? write the type of metal, based on your examination of the periodic table. type your answer here. (score for question 4: of 5 points) make a general statement about the reactivity of the metals in this experiment. type your answer here.
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For the reaction, 4 a(g) + 3 b(g) => 2 c(g), the following data were obtained at constant temperature. experiment initial[a],mol/l initial [b],mol/l initial rate, m/min 1 0.200 0.150 5.00 2 0.400 0.150 10.0 3 0.200 0.300 10.0 4 0.400 0.300 20.0 which of the following is the correct rate law for the reaction? 1. rate = k[a]2[b]2 2. rate = k[a][b] 3. rate = k[a]2[b] 4. rate = k[a][b]2
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Fifty grams (50.0) of hot water at a temperature of 65.0°C is mixed with 40.0 grams of cold water. T...
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