A chemist must dilute 61.9 mL of 548. nM aqueous sodium carbonate (Na2CO3) solution until the concentration falls to 484. nM . He'll do this by adding distilled water to the solution until it reaches a certain final volume. Calculate this final volume, in milliliters. Round your answer to 3 significant digits.

The final volume will be "70.08 mL".

Explanation:

The given values are:

Molar mass,

M1 = 548 nM

or,

     =

M2 = 484 nM

or,

      =  

Volume,

V1 = 61.9 mL

V1 = ?

By using the expression, we get

⇒

or,

⇒            

By substituting the values, we get

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