If 1.25 g of water is heated from 20.0 degrees Celsius to 45.0 degrees Celsius and has a specific heat of 4.18 J/gC, how much heat energy does it contain?

Heat energy contained by water is 130.625 J.

Explanation:

Given: Mass = 1.25 g

Specific heat =

Initial temperature =

Final temperature =

Formula used to calculate heat energy is as follows.

where,

q = heat energy

m = mass of substance

= initial temperature

= final temperature

Substitute the values into above formula as follows.

Thus, we can conclude that heat energy contained by water is 130.625 J.

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