If only 0.225 g of Ca(OH)2 dissolves in enough water to give 0.100 L of aqueous solution at a given temperature, what is the Ksp value for calcium hydroxide at this temperature

The value for calcium hydroxide at this temperature is .

Explanation:

Given: Mass of = 0.225 g

Volume = 0.100 L

As moles is the mass of substance divided by its molar mass.

So, moles of (molar mass = 74 g/mol) is calculated as follows.

Molarity is the number of moles of substance present in a liter of solution.

Hence, molarity of given solution will be as follows.

The equation for dissociation of   is as follows.

This means that and . Hence, value for this reaction is calculated as follows.

Thus, we can conclude that the value for calcium hydroxide at this temperature is .

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