1. How many grams of Ag+ are present in 2.24 grams of silver
sulfite?
grams Agt.
2. How many grams of silver sulfite contain 1.75 grams of Agt?
grams silver sulfite.

1. 0.82 gram of Ag+

2. 4.79 g of Ag₂O₃S

Explanation:

From the given information:

Total amount of Ag₂O₃S = 2.24 grams

Atomic mass of Ag+ =107.86 g/mole

molar mass of Ag₂O₃S = 295.8  g/mole

∴

The mass of the Silver (Ag) in grams is:

= 0.82 gram of Ag+

2.

Here, the total amount of Ag₂O₃S = unknown

Atomic mass of Ag+ = 107.86 g/mole

molar mass of Ag₂O₃S = 295.8 g/mole

amount of Ag+  = 1.75 g

∴

The mass of Ag₂O₃S =

= 4.79 g of Ag₂O₃S

n2(g) + 3h2-> 2nh3(g)   this is the balanced equation

note the mole ratio between n2, h2 and nh3.   it is 1 : 3 : 2   this will be important.

moles n2 present = 28.0 g n2 x 1 mole n2/28 g = 1 mole n2 present

moles h2 present = 25.0 g h2 x 1 mole h2/2 g = 12.5 moles h2 present

based on mole ratio, n2 is limiting in this situation because there is more than enough h2 but not enough n2.

moles nh3 that can be produced = 1 mole n2 x 2 moles nh3/mole n2 = 2 moles nh3 can be produced

grams of nh3 that can be produced = 2 moles nh3 x 17 g/mole = 34 grams of nh3 can be produced

note:   the key to this problem is recognizing that n2 is limiting, and therefore limits how much nh3 can be produced.