Chemistry, 24.05.2021 01:00, vixxs345

If O2 was the excess reagent, 8.3 mol of H2S were consumed, and 13.7 moles of water were collected after the reaction has gone to completion, what is the
theoretical yield of the reaction in moles? ROUND TO THE NEAREST TENTH!!
2H2S(g) + 302(g) → 2504(g) + 2H2O(g)

Answers: 2

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If O2 was the excess reagent, 8.3 mol of H2S were consumed, and 13.7 moles of water were collected...

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If O2 was the excess reagent, 8.3 mol of H2S were consumed, and 13.7 moles of water were collected after the reaction has gone to completion, what is the theoretical yield of the reaction in moles? ROUND TO THE NEAREST TENTH!! 2H2S(g) + 302(g) → 2504(g) + 2H2O(g)

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If O2 was the excess reagent, 8.3 mol of H2S were consumed, and 13.7 moles of water were collected after the reaction has gone to completion, what is the
theoretical yield of the reaction in moles? ROUND TO THE NEAREST TENTH!!
2H2S(g) + 302(g) → 2504(g) + 2H2O(g)