1) Calculate the temperature change for mercury if 160 g of the metal absorbs 1500 J of heat energy. Mercury's specific heat is 0.14 J/g°C. 2) How much heat is given out when 85 g of lead cools from 200.0°C? The specific heat of lead is 0.11 J/g°C

3) What is the final temperature of a substance if 1404 J of energy is added to 38 g of it at 26°C? The specific heat is 0.24 J/g°C

1. 66.96°C

2. -1776.5J

3. 179.9°C

Explanation:

Using the formula;

Q = m × c × ∆T

Where;

Q = amount of heat (J)

m = mass (g)

c = specific heat capacity (J/g°C)

∆T = change in temperature (°C)

QUESTION 1:

∆T = ?

m = 160g

c = 0.14 J/g°C

Q = 1500 J

1500 = 160 × 0.14 × ∆T

1500 = 22.4∆T

∆T = 1500/22.4

∆T = 66.96°C

QUESTION 2:

Q = ?

m = 85g

c = 0.11 J/g°C

∆T = 10°C - 200°C = -190°C

Q = 85 × 0.11 × -190

Q = -1776.5J

QUESTION 3:

Q = 1404 J

m = 38g

c = 0.24 J/g°C

Final temperature = ?

Initial temperature = 26°C

1404 = 38 × 0.24 × (T2 - 26)

1404 = 9.12 (T2 - 26)

1404 = 9.12T2 - 237.12

9.12T2 = 1404 + 237.12

9.12T2 = 1641.12

T2 = 1641.12 ÷ 9.12

T2 = 179.9°C

answers: to make sure that all of the broken pieces of tablet were added to the water, to allow for fair comparison of all three trials, with different particle sizes to avoid experimental error