74g of Ca(OH)2 (74 g/mol) in 340 ml solution

This question is asking to calculate the molarity of the solution based on the information provided.

The answer is 2.94M

Explanation:

Molarity of Ca(OH)2 solution = number of moles (n) ÷ volume (V)

Using the formula below to calculate number of moles of Ca(OH)2.

mole = mass/molar mass

Molar mass of Ca(OH)2 = 74 g/mol

mole = 74g/74g/mol

mole = 1mol

Volume of Ca(OH)2 solution = 340ml = 340/1000 = 0.340 L

Molarity = 1/0.340

Molarity = 2.94M

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