What is the molarity of a solution composed of 4.27 g of potassium iodide (KI) dissolved in
enough water to make 0.304 L of solution?
Answer in units of M.

0.0845 M

Explanation:

First we convert 4.27 grams of potassium iodide into moles, using its molar mass:

Now we calculate the molarity of the solution, using the number of moles and the given volume:

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.

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