Please help no links Ms. Daly had Hydrogen gas that was cooled from 100 °C to 50.5°C. The new volume was 20 L. What was its original volume?
20.
50.

23 L

Explanation:

We'll begin by converting celsius temperature to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

Initial temperature (T₁) = 100 °C

Initial temperature (T₁) = 100 °C + 273

Initial temperature (T₁) = 373 K

Final temperature (T₂) = 50.5 °C

Final temperature (T₂) = 50.5 °C + 273

Final temperature (T₂) = 323.5 K

Finally, we shall determine the initial volume of gas. This can be obtained as follow:

Initial temperature (T₁) = 373 K

Final temperature (T₂) = 323.5 K

Final volume (V₂) = 20 L

Initial volume (V₁) =?

V₁/T₁ = V₂/T₂

V₁ / 373 = 20 / 323.5

Cross multiply

V₁ × 323.5 = 373 × 20

V₁ × 323.5 = 7460

Divide both side by 323.5

V₁ = 7460 / 323.5

V₁ = 23 L

Thus, the original volume of the gas is 23 L

answer

i think the answer is a) as air pressure in an area increases, the density of the gas particles in that area decreases.

hope it