How many grams of NiNi are formed from 55.3 g of Ni2O3?

2Ni2O3(s)⟶4Ni(s)+3O2(g)

39.2 g

Explanation:

2Ni₂O₃(s) ⟶ 4Ni(s) + 3O₂(g)

First we convert 55.3 g of Ni₂O₃ into moles, using its molar mass:

55.3 g ÷ 165.39 g/mol = 0.334 mol Ni₂O₃

Then we convert 0.334 Ni₂O₃ moles into Ni moles, using the stoichiometric coefficients of the balanced reaction:

0.334 mol Ni₂O₃ * = 0.668 mol Ni

Finally we convert 0.668 Ni moles into grams, using its molar mass:

0.668 mol * 58.69 g/mol = 39.2 g

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