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.![pH = - log [H^{+}]](/tpl/images/1336/4302/d6b92.png)
![pH = -log [H^{+}]\\2.7 = -log [H^{+}]\\conc. of H^{+} = 1.99 \times 10^{-3}](/tpl/images/1336/4302/3ee68.png)
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The pOH of a solution of KOH is 11.30. What is the [H*] for this solution?...
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