HELP!! I don’t understand this one bit

for this qn, you need to find out who is the limiting reagent. in this case i will do it this way.

if 49.6g of potassium hydrogen sulfate is present, 49.6g of potassium hydroxide is required. thus, there are lesser amt of potassium sulfate present than required thus KOH is the limiting reagent. if you do it the opposite way, you will realise there are MORE potassium hydrogen sulfate present than required, thus the another party, KOH, is limiting.

the next part you need to convert to mole but i am not really gd at it.

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.

the answer is na (sodium)