What is the pressure of gas at 496 Liters and 200 Kelvin if the original pressure was 0.250 atm. at 300 liters and 400 kelvin?

0.076 atm

Explanation:

Using the combined gas law formula;

P1V1/T1 = P2V2/T2

Where;

P1 = initial pressure (atm)

P2 = final pressure (atm)

T1 = initial temperature (K)

T2 = final temperature (K)

V1 = initial volume (L)

V2 = final volume (L)

According to the information provided in this question;

P2 = ?

P1 = 0.250 atm

V2 = 496 L

V1 = 300 L

T2 = 200K

T1 = 400K

Using P1V1/T1 = P2V2/T2

0.250 × 300/400 = P2 × 496/200

75/400 = 496 P2/200

0.1875 = 2.48P2

P2 = 0.1875 ÷ 2.48

P2 = 0.076 atm

the number of valence electrons for each molecule or ion is shown beneath the structure. remember hydrogen will not have more than two electrons. this hydrogen is part of a covalent bond (sharing two electrons). a double bond here would cause hydrogen to share four electrons with phosphorus.