A student ran the following reaction in the laboratory at 1080 K: 2SO3(g) 2SO2(g) + O2(g) When she introduced SO3(g) at a pressure of 0.948 atm into a 1.00 L evacuated container, she found the equilibrium partial pressure of SO3(g) to be 0.369 atm. Calculate the equilibrium constant, Kp, she obtained for this reaction. Kp =

0.078

Explanation:

The equation is :

Initial         0.948                  -----                   ----

Change      -2x                     +2x                  +x

Final          0.369                  2x                    x

So the total pressure must reman same = 0.948

And the total pressure = partial pressure of all gases

0.948   =   ( 0.369 + 2x + x )

0.948  =  0.369 + 3x

  = 0.193 atm

So the partial pressure of  = 0.193 x 2

                                                   = 0.386 atm

Partial pressure of  =  0.193 atm

Therefore,

    = 0.078

definition

                    entropy is a measure of the randomness or the extent of disorder of a chemical process.

                      enthalpy is a measure of the heat change of a reaction occurring at a constant pressure.

measurement units:

                        entropy is measured in joule per kelvin (jk⁻¹)   whereas enthalpy is measured in joule per mole (jmol⁻¹)

requirements:

                            entropy has no requirements or limits, and its change is measured by the division between the heat change of the chemical process and the temperature.

                              in contrast, enthalpy can only be related to the heat change of the reaction under standard conditions.