solid iron with copper (II) sulfate. Assume the iron will form a +2 charge on the product side. Write the balanced equation for this reaction

hey here is the answer to your question.

Explanation:

1) Write a balanced equation for the reaction occurring. (*Iron occurs in a few different oxidation states, but I will assume we're referring to Fe(II) or Fe2+)

Fe + CuSO4 -> Cu + FeSO4

2) Calculate the number of moles of each reactant.

Fe: 1.924 g * (1 mol / 55.85 g) = 0.03455 mol Fe

CuSO4: 0.1363 L * (0.0750 mol / 1 L) = 0.01022 mol CuSO4

3) Determine the limiting reactant. Because we have fewer moles of copper(II) sulfate and are reacting both reactants in a 1:1 ratio, we will run out of copper(II) sulfate first, making it the limiting reactant.

4) Convert moles of the limiting reactant to moles and grams of product of interest.

0.01022 CuSO4 (1 mol Cu / 1 mol CuSO4 ) (63.55 g Cu / 1 mol Cu) = 0.6495 g Cu

assuming that your periodic table has eighteen columns, you should highlight   the four elements in the third column from the left of the table.

neutral atoms of elements after calcium contain d electrons. the energy of d orbitals of a particular main shell lies between the energy of the s and p orbitals of the next main shell. for example, electrons in the have energy higher than those in the orbital while lower than those of the orbital.

by the aufbau principle, electrons fill orbitals one at a time, starting from those of the lowest energy. the orbital is therefore filled right after orbitals and before orbitals.  

potassium has electron configuration and calcium . the s orbital of a main shell holds a maximum of two electrons. the next element would thus have the electron configuration and satisfy the requirements.

a neutral atom of the element contains three electrons on top of the most recent noble gas element. it should thus be placed in the third column of the periodic table. both scandium and yttrium would satisfy the conditions. an aufbau diagram indicates that the 4f orbital is filled before the 5d. however, it appears that exceptions exists for both lanthanum and actinium. neutral atoms of the two d-block elements also demonstrate the and should be highlighted as well.