Pls solve, needed ASAP

1. Cl2+2Nabr--> 2NaCl +Br2

2. Already balanced

3. Ca(ClO3)2-->CaCl2+3O2

3. 2AgNO3 + K2SO4--> Ag2SO4 + 2KNO3

4. Already balanced

5. 2C8H18+25O2-->16CO2+25H2O

Sorry for late

the grams   of   barium that   are in   2.3 x 10^23   atoms of barium   is   52.4 g (answer c)

    calculation

mass = moles   of ba   x molar   mass of ba

  molar mass of ba from periodic table=   137.3 g/mol

  use the   avogadro's law   constant   to   calculate the moles of barium

  that   is     1 mole =   6.02   x 10^23 atoms

                    ? moles = 2.3 x 10^23   atoms

by cross   multiplication

=(1 mole   x 2.3x 10^23 atoms)   / 6.02   x10^23 atoms)=   0.382   moles

mass   is therefore = 137.3   g/mol x 0.382 mol = 52.4 ( answer c)

explanation: