Calculate the mass defect and the nuclear binding energy of nitrogen-14. The mass of a proton is 1.00728 amu, and the mass of a neutron is 1.00866 amu.
The mass of a nitrogen-14 atom is 14.00307 amu.

The mass defect of nitrogen-14 is
amu. Round to the decimal place.
The nuclear binding energy of one nitrogen-14 atom is
x 10A J. Round to 3 significant digits.
A:

1.62 * 10^-11 J

Explanation:

Nitrogen-14 nucleus has seven neutrons and seven protons. So;

Total mass of protons = 7(1.00728 amu)

Total mass of neutrons = 7(1.00866 amu)

Total mass of nucleons = 7(1.00728 amu) + 7(1.00866 amu)= 14.11158 amu

Mass of Nitrogen-14 nucleus = 14.00307 amu

Mass defect = 14.11158 amu - 14.00307 amu = 0.10851 amu = 1.801852171 * 10^-28 Kg

Binding energy = Δmc^2

Where;

Δm = mass defect

c = speed of light

Binding energy = 1.801852171 * 10^-28 Kg * (3 * 10^8)^2

Binding energy = 1.62 * 10^-11 J

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explanation:

dasdad

the answer for sodium is 0.186

the answer for rubidium is 0.251