Silver chloride is virtually insoluble in water so that the reaction appears to go to completion. How many grams of solid NaCl must be added to 25.0 mL of 0.366 M AgNO3 solution to completely precipitate the silver

0.535 g

Explanation:

The reaction that takes place is:

First we calculate how many AgNO₃ moles are there in 25.0 mL of a 0.366 M solution, using the definition of molarity:

Converting 25.0 mL to L ⇒ 25.0 / 1000 = 0.025 L

Then we convert AgNO₃ moles into NaCl moles:

Finally we convert NaCl moles into grams, using its molar mass:

the dependant variable is spilled water

the independent is the heat

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