If 500 mL expandable cylinder with a pressure of 500 mmHg was filled until the volume was 1.2 atm. What is the
new volume?

0.274 L

Explanation:

Applying Boyle's law,

PV = P'V' Equation 1

Where P = Initial pressure, V = Initial volume, P' = Final pressure, V' = Final volume.

make V' the subject of the equation,

V' = PV/P' Equation 2

From the question,

Given: P = 500 mm Hg, V = 500 mL = 0.5 L, P' = 1.2 atm = 912 mm Hg

Substitute these values into equation 2

V' = (0.5×500)/912

V' = 0.274 L

Hence the new volume is 0.274 L

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

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