How many grams of KI would you need to prepare 0.50 g of 7.0% KI (m/m) solution?

fomula; ( x = mutiplacation btw)

% m/m = m(solute) / m(solution) x 100%

0.50g x 70% = m/m x 100%

0.5g x 70% / 100% = 3.5 g KI

(both % cancle each other)

Explanation:

heads up might be wrong i did it myself

he uptake of drugs from the intestine is often strongly influenced by diffusion. for example, consider a water-insoluble steroid for treating inflammation that is solubilized in aggregates of detergent molecules, called micelles. these micelles, aggregates of 80 soap molecules, have a molecular weight of 24,000, a diameter of 2.6 nm, and a charge of -27. the positively charge ions (counterions) in this system are na".

the answer is barium and copper bromide