Problem #6 If you dissolve lead (II) nitrate and potassium iodide in water they will react to form lead (II) iodide and potassium nitrate 1). Write the equation for this reaction, then balance the equation
2). Calculate the grams of lead(II) iodide that can be produced from 5.00 moles of potassium iodide.
3).Calculate the grams of lead (II) iodide that can be reproduced from 75.00 grams of potassium iodide.​

There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. in the first step, calcium carbide and water react to form acetylene and calcium hydroxide: cac2 (s) + 2h2o (g) → c2h2 (g) + caoh2 (s) =δh−414.kj in the second step, acetylene, carbon dioxide and water react to form acrylic acid: 6c2h2 (g) + 3co2 (g) + 4h2o (g) → 5ch2chco2h (g) =δh132.kj calculate the net change in enthalpy for the formation of one mole of acrylic acid from calcium carbide, water and carbon dioxide from these reactions. round your answer to the nearest kj .