Can someone please help me im stuck​

The answers to your questions are given below.

Explanation:

1. __H₂ + __O₂ —> __H₂O

The above equation can be balance as follow:

H₂ + O₂ —> H₂O

There are 2 atoms of O on the left side and 1 atom on the right side. It can be balance by writing 2 before H₂O as shown below:

H₂ + O₂ —> 2H₂O

There are 2 atoms of H on the left side and a total of 4 atoms on the right side. It can be balance by writing 2 before H₂ as shown below:

2H₂ + O₂ —> 2H₂O

Now the equation is balanced.

Elements >>> Reactants >>> Products

H >>>>>>>>> 4 >>>>>>>>>>> 4

O >>>>>>>>> 2 >>>>>>>>>>> 2

2. __ P₄ + __O₂ —> __P₂O₃

The above equation can be balance as follow:

P₄ + O₂ —> P₂O₃

There are 4 atoms of P on the left side and 2 atoms on the right side. It can be balance by writing 2 before P₂O₃ as shown below:

P₄ + O₂ —> 2P₂O₃

There are 2 atoms of O on the left side and a total of 6 atoms on the right side. It can be balance by writing 3 before O₂ as shown below:

P₄ + 3O₂ —> 2P₂O₃

Now, the equation is balanced

Elements >>> Reactants >>> Products

P >>>>>>>>> 4 >>>>>>>>>>> 4

O >>>>>>>>> 6 >>>>>>>>>>> 6

air

in a tire you fill a tire with air

then a couple days later you check the air pressure in the tire

hope this mark me brainliest

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole