You are about to start a cell biology experiment that requires a number of different chemical reagents. You have an unlimited supply of water and the following materials available in the lab to make your solutions; 500g dry glucose 1500 mL of 40% TRIS-buffer solution 150 mL of 0.3 molar ampicillin 2L of 35% SDS Using precise numerical values (to one decimal place, do NOT include units), describe how you will prepare 150 mL of 8% TRIS-buffer.

The answer is "212.5 ml"

Explanation:

Please find the complete question in the attached file.

In 2 ml of SDS it makes 120 ml of SDS.

To mix x ml of SDS

added water

So we have to add 24ml from SDS and add 96ml water to male 120ml SDS.

1500ml of 40% Tris Buffer solution  

Let us assume we have to mix y ml of 40% Tris buffer solution  

added water  

So we have to add 37.5 ml from 40% Tris Buffer and add 212.5 ml water to male 250 ml 6% Tris Buffer.

for points guys